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Euler Formula: e^(pi*i) = -1 There is the well known identity that e^(ix) = cos(x) + i.sin(x)
Then let x = pi. cos(pi) = -1, sin(pi) = 0 so e^(i.pi) = cos(pi)
+ i.sin(pi) = -1 + 0 and so e^(i.pi) = -1 |